Easa Atpl Question Bank -

Wait — option a says DOI = 114.8 → difference = 2.4. That means Crew index = 2.4. Then 2.4 = (410 × 142) / CF → CF = (410 × 142) / 2.4 ≈ 24,258. So CF = 24,258. Then BEM index = (34,560 × arm_BEM) / 24,258 = 112.4 → arm_BEM = (112.4 × 24,258) / 34,560 ≈ 78.9 m — plausible.

Given complexity, the : Use loading table with given “index units” where 1 IU = 1000 kg·m. Then BEM moment = 112.4 × 1000 = 112,400 kg·m. Crew moment = 410 × 142 = 58,220 → total moment = 170,620 kg·m → DOI = 170,620 / 1000 = 170.6 — wrong. So not /1000. easa atpl question bank

Actually: only if index units are moment/constant and the constant is the same. Let’s test option a: DOI 114.8. Wait — option a says DOI = 114

Given BEM index = 112.4 at 34,560 kg. Crew: Mass 410 kg, arm 142.0. To add index, use: Added Index = (Mass × Arm) / (Reference constant) ? Wait — in EASA questions, often the index is a simple moment / 1000 or moment / 100,000 . We must deduce the Index Unit (IU). So CF = 24,258

Index formula typically: , but in this question bank, they provide index directly for BEM and arm values for others. We must compute additional moment index from crew:

? No — wrong; Index is not average.

Better approach: Use (common in EASA performance). Let’s verify: Moment_BEM = Index × 10,000 = 1,124,000. Then arm_BEM = Moment / Mass = 1,124,000 / 34,560 ≈ 32.5 m — plausible. Good.