Ncert Solutions | Class 10 Electricity

Answer: Power ( P = V \times I = 220 \times 5 = 1100 , \text{W} ) Energy = ( P \times t = 1100 \times 2 = 2200 , \text{Wh} = 2.2 , \text{kWh} ) Chapter Exercise Solutions (Page 221–222) Q1. A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R', then the ratio R/R' is: (a) 1/25 (b) 1/5 (c) 5 (d) 25 Answer: Each piece resistance = R/5. Parallel: 1/R' = 5/(R/5) → R' = R/25 → R/R' = 25 → (d)

Answer: From Ohm’s law ( V = IR ), if ( R ) constant and ( V ) becomes half, ( I ) also becomes half. class 10 electricity ncert solutions

(a) 1:2 (b) 2:1 (c) 1:4 (d) 4:1 Answer: Each R, series ( R_s = 2R ), parallel ( R_p = R/2 ) Heat ( H = V^2 t / R ) → ( H_s / H_p = R_p / R_s = (R/2) / (2R) = 1/4 ) → (c) Answer: Power ( P = V \times I

Here are the (based on the latest NCERT textbook). If the equivalent resistance of this combination is

Answer: Total R = 0.2+0.3+0.4+0.5+12 = 13.4 Ω ( I = 9 / 13.4 \approx 0.67 , \text{A} ) (same in series)